36x=162+2x^2

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Solution for 36x=162+2x^2 equation: 



36x=162+2x^2

We move all terms to the left:

36x-(162+2x^2)=0

We get rid of parentheses

-2x^2+36x-162=0

a = -2; b = 36; c = -162;
Δ = b2-4ac
Δ = 362-4·(-2)·(-162)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-36}{-4}=+9$

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